Question

\frac{3(x^{2}-11) }{5} - \frac{2(x^{2}-60) }{7} =36

Answer 1

Объяснение:

$\frac{3x^2-33}{5} -\frac{2x^2-120}{7} -\frac{36}{1} =0\\$

$\frac{21x^2-231-10x^2+600-1260}{35}=0\\ 11x^2-891=0\\11x^2=891\\x^2=891:11\\x^2=81\\x_1=9\\x_2=-9$

Answer 2

$\displaystyle \tt \frac{3\cdot(x^2-11)}{5}-\frac{2\cdot(x^2-60)}{7}=36\\\\ \displaystyle \tt \frac{3\cdot(x^2-11)}{5}-\frac{2\cdot(x^2-60)}{7}-36=0\\\\\displaystyle \tt \frac{21\cdot(x^2-11)-10\cdot(x^2-60)-1260}{35}=0\\\\ \displaystyle \tt 21x^2-231-10x^2+600-1260=0\\\displaystyle \tt 11x^2-891=0\\\displaystyle \tt 11x^2=891\\\displaystyle \tt x^2=891\div11\\\displaystyle \tt x^2=81\\\displaystyle \tt x=б\sqrt{81}\\\displaystyle \tt \bold{x_1=9}\\\displaystyle \tt \bold{x_2=-9}$