Question

1" class="latex-formula" id="TexFormula1" src="https://tex.z-dn.net/?f=%20%5Csqrt%7B3%7D%20%5Ctan%28%3F%29%20%28x%20%2B%20%5Cfrac%7B%5Cpi%7D%7B6%7D%20%29%20%3E%201" title=" \sqrt{3} \tan(?) (x + \frac{\pi}{6} ) > 1">
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Answer 1

$\pi n < x < \frac{\pi}{3} + \pi n$

Объяснение:

$\sqrt{3} tan(x + \frac{\pi}{6} ) 1\\\\tan(x + \frac{\pi}{6} ) \frac{1}{\sqrt{3}} \\\\tan(x + \frac{\pi}{6} ) tan \frac{\pi}{6} \\\\\frac{\pi }{6} + \pi n < x + \frac{\pi}{6} < \frac{\pi}{2} + \pi n \\\\\frac{\pi }{6} + \pi n - \frac{\pi}{6} < x < \frac{\pi}{2} + \pi n - \frac{\pi}{6}\\\\\pi n < x < \frac{\pi}{3} + \pi n$