Question

У выражение:x+4/x-3×3x-9/x^2+8x+16:15/xy+4y​

Answer 1

$\frac{x + 4}{x - 3} \times \frac{3x - 9}{ {x}^{2} + 8x + 16 } \div \frac{15}{xy + 4y} = \frac{x + 4}{x - 3} \times \frac{3(x - 3)}{ {(x + 4)}^{2} } \times \frac{y(x + 4)}{15} = \frac{3}{x + 4} \times \frac{y(x + 4)}{15} = \frac{3y}{15} = \frac{y}{5}$