2(x^2+6x+1)^2(x^2+1)(x^2+6x+1)+2(x^2+1)^2=0методом замены

Question

Алгебра: 2(x^2+6x+1)^2(x^2+1)(x^2+6x+1)+2(x^2+1)^2=0методом замены​

vkjfnjkvd · Accepted Answer

X^2 (x + 5) - 25(x + 5) = 0
(x + 5)(x^2 - 25) = 0
(x + 5)(x - 5)(x + 5) = 0
(x - 5)(x + 5)^2 = 0

1)
x - 5 = 0
x = 5; 2)x^2 (x + 5) - 25(x + 5) = 0   (x + 5)* (x^2 - 25) = 0
(x + 5)^2 = 0   x x = - 5;
ответ:
- 5; 5 + 5 = 0

2(x^2+6x+1)^2(x^2+1)(x^2+6x+1)+2(x^2+1)^2=0методом замены​

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