Question

Найдите значение sin a,cos a,tg a,ctg a(если они существуют)при: 1)a=3π 2)а=-4π 3)а=-π/2(дробью) 4)а=5π/2(дробью) 5)а=-5π/6(дробью) 6)а=3π/4(дробью)

Answer 1

sin3π = 0

cos3π = -1

tg3π = 0

ctg3π не существует

sin(-4π) = 0

cos(-4π) = 1

tg(-4π) = 0

ctg(-4π) не существует

sin(-π/2) = -1

cos(-π/2) = 0

tg(-π/2) не существyет

ctg(-π/2) = 0

sin(5π/2) = 1

cos(5π/2) = 0

tg(5π/2) не существует

cos(5π/2) = 0

sin(-5π/6) = -1/2

cos(-5π/6) = -√3/2

tg(-5π/6) = 1/√3

ctg(-5π/6) = √3

sin(3π/4) = √2/2

cos(3π/4) = - √2/2

tg(3π/4) = -1

ctg(3π/4) = -1