Question

Сократите дробь: 5а/a= a^2b^3/a^4b^2= ab^3/a^2b= a(a+b)/a^3(a+b)= a^2(a-b)/a(a-b)= 15ab^3/3a^2b^3= 24a^3(a+b)/16b(a+b)= 18a(a-b)^2/27(a-b)^3= 3a(a-b)/6a(b-a)= 3a(a-b)/6a(b-a)^2= 3a(a-b)/6a(b-a)^3= (a-b)^2/(b-a)^3= (a-b)^2/(b-a)^4= решите какие знаете ! заранее !

Answer 1

$\frac{5a}{a}=5;$

$\frac{a^2b^3}{a^4b^2}=\frac{b}{a^2};$

$\frac{ab^3}{a^2b}=\frac{b^2}{a};$

$\frac{a(a+b)}{a^3(a+b)}=\frac{1}{a^2};$

$\frac{a^2(a-b)}{a(a-b)}=a;$

$\frac{15ab^3}{3a^2b^3}=\frac{5}{a};$

$\frac{24a^3(a+b)}{16b(a+b)}=\frac{3}a^3{2b};$

$\frac{18a(a-b)^2}{27(a-b)^3}=\frac{2a}{3(a-b)};$

$\frac{3a(a-b)}{6a(b-a)}=\frac{-1}{2};$

$\frac{3a(a-b)}{6a(b-a)^2}=\frac{1}{2(a-b)};$

$\frac{3a(a-b)}{6a(b-a)^3}=\frac{-1}{2(a-b)^2};$

$\frac{(a-b)^2}{(b-a)^3}=\frac{1}{b-a};$

$\frac{(a-b)^2}{(b-a)^4}=\frac{1}{(a-b)^2}$