Question

решить 2 задачи по алгебре

Answer 1

Объяснение:

$10 \sqrt{3} - 4 \sqrt{48} - \sqrt{75} = 10 \sqrt{3} - 4 \sqrt{16 \times 3} - \sqrt{25 \times 3} = 10 \sqrt{3} - 16 \sqrt{3} - 5 \sqrt{3} = - 11 \sqrt{3}$

$(5 \sqrt{2} - \sqrt{18} ) \times \sqrt{2} = (5 \sqrt{2} - \sqrt{9 \times 2} ) \times \sqrt{2} = (5 \sqrt{2} - 3 \sqrt{2} ) \times \sqrt{2} = 2 \sqrt{2} \times \sqrt{2} = 4$

${(3 - \sqrt{2)} }^{2} = 9 - 6 \sqrt{2} + 4 = 11 - 6 \sqrt{2}$

$( \sqrt{5} - \sqrt{18} )( \sqrt{5} + \sqrt{18} ) + \sqrt{225} = 5 - 18 + 15 = 2$

$\frac{6 + \sqrt{6} }{ \sqrt{6} } = \frac{6 + \sqrt{6} }{ \sqrt{6} } \times \frac{ \sqrt{6} }{ \sqrt{6} } = \sqrt{6} + 1$