Question

У=-1/х^2
У=3/х^4/3
Найдите производную функции​

Answer 1

$1)y = - \frac{1}{ {x}^{2} } = - {x}^{ - 2} \\$

$y' = - ( - 2) \times {x}^{ - 3} = \frac{2}{ {x}^{3} } \\$

$2)y = \frac{3}{ {x}^{ \frac{4}{3} } } = 3 {x}^{ - \frac{4}{3} } \\$

$y' = 3 \times ( - \frac{4}{3} ) {x}^{ - \frac{4}{3} - 1} = - 4 {x}^{ - \frac{7}{3} } = \\ = - \frac{4}{ {x}^{2} \sqrt[3]{x} }$

Answer 2

\begin{gathered}y' = 3 \times ( - \frac{4}{3} ) {x}^{ - \frac{4}{3} - 1} = - 4 {x}^{ - \frac{7}{3} } = \\ = - \frac{4}{ {x}^{2} \sqrt[3]{x} } \end{gathered}

y

′

=3×(−

3

4

)x

−

3

4

−1

=−4x

−

3

7

=

=−

x

2

3

x

4

Объяснение:

как то так вроде