РЕШИТЬ НЕРАВЕНСТВО 1. (x – 1)(x + 2) 0 2 ). x2 – 4x – 5 ≥ 0 3) – 3x2 – 5x + 2 0 - id1781559920221128 от DiaGirlNya 28.11.2022 06:56

Question

Алгебра: РЕШИТЬ НЕРАВЕНСТВО 1. (x – 1)(x + 2) 0 2 ). x2 – 4x – 5 ≥ 0 3) – 3x2 – 5x + 2 0

DiaGirlNya · Accepted Answer

1) 10х + 4 = 7х + 19 10х - 7х = 19 - 4 3х = 15 х = 15 / 3 х = 5 2) 9 - 6х = 8х + 7 -6х - 8х = 7 - 9 -14х = -2 х = -2 / -14 х = 7 3) 5(х+2) = 1 5х + 10 = 1 5х = 1 - 10 х = -9 / 5 х = -1 4/5 = -1,8 4) 7(2х + 3) = 12х + 11 14х + 21 = 12х + 11 14х - 12х = 11 - 21 2х = - 10 х = -10 / 2 х = -5 5) 7(-4 + х) = 3х - 4 - 28 + 7х = 3х - 4 7х - 3х = -4 + 28 4х = 24 х = 24 / 4 х = 6 6) 2(х + 7) - 9 = -2х 2х + 14 - 9 = -2х 2х + 2х = 9 - 14 4х = -5 х = -5 / 4 х = -1,25 7) -3 (5 - х) = 11 + 2х -15 + 3х = 11 + 2х...

РЕШИТЬ НЕРАВЕНСТВО

1. (x – 1)(x + 2) < 0 2 ). x2 – 4x – 5 ≥ 0 3) – 3x2 – 5x + 2 > 0

MOGZ ответил

РЕШИТЬ НЕРАВЕНСТВО 1. (x – 1)(x + 2) < 0 2 ). x2 – 4x – 5 ≥ 0 3) – 3x2 – 5x + 2 > 0

MOGZ ответил

РЕШИТЬ НЕРАВЕНСТВО

1. (x – 1)(x + 2) < 0 2 ). x2 – 4x – 5 ≥ 0 3) – 3x2 – 5x + 2 > 0