Question

Найдите функцию,обратную функции y = 3 - x^2? x> =0.

Answer 1

$y = 3 - x^2 \\\ x^2=3-y \\\ x= \sqrt{3-y} \\\\ y= \sqrt{3-x}$

Answer 2

$y=3-x^2; x \geq 0$
=>$y<=3; 3-y \geq 0$

$y(x)=3-x^2$
$x^2=3-y$
$x=\sqrt{3-y}$
$x(y)=\sqrt{3-y}$
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$y(x)=\sqrt{3-x}$ - обратная