Question

Найдите значение выражения 7√2 +√2(√3 -4)+3√6​

Answer 1

$7\sqrt{2} +\sqrt{2}(\sqrt{3}-4)+3\sqrt{6}=7\sqrt{2}+\sqrt{2}\cdot \sqrt{3} -\sqrt{2}\cdot 4+3\sqrt{6} =\\\\=7\sqrt{2} +\sqrt{6}-4\sqrt{2} +3\sqrt{6}=\boxed{3\sqrt{2}+4\sqrt{6}}$

Answer 2

7√2+√2(√3-4)+3√6=7√2+√6-4√2+3√6=7√2-4√2+√6+3√6=3√2+4√6=3√2+4√2√3=√2(3+4√3)=

1.41(3+4*1.73)=1.41(3+6.92)=1.41*9.92=13.9872

√2≈1.41

√3≈1.73