Question

Решите систему уравнений (х-8)(у-6)=0 у-2/х+у-10=4

Answer 1

$\left \{ {{(x-8)(y-6)=0} \atop {y-2=4x+4y-40}} \right.$
$\left \{ {{(x-8)(y-6)=0} \atop {y= \frac{38-4x}{3} }} \right.$
$(x-8)( \frac{38-4x}{3} -6)=0$
$(x-8)( \frac{20-4x}{3} )=0$
$x-8=0$ и$\frac{20-4x}{3} =0$
$x=8$ и $x=5$
1.$\left \{ {{x=8} \atop { \frac{y-2}{8+y-10}=4 }} \right.$
$\left \{ {{x=8} \atop { \frac{y-2}{y-2}=3 }} \right. (1 \neq 3)$ - не уд.
2.$\left \{ {{x=5} \atop { \frac{y-2}{5+y-10}=4 }} \right.$
$\left \{ {{x=5} \atop {y=6}} \right.$