1)sin 2x*sqrt(4-x^2)=0
sin2x=0; sqrt(4-x^2)=0; ОДЗ: -2<=x<=2
x=пи n/2 4-x^2=0;
x^2=4
x1=-2 x2=2
2) sqrt(3)^(sin^2x-1)*3sqrt(3)=корень 4 степени из 3^6
3^1/2(sin^2x-1)*3sqrt(3)=sqrt(3^3)
3^1/2(sin^2x-1)*3sqrt(3)=3sqrt(3)
3^1/2(sin^2x-1)=1 (3^0)
1/2 (sin^2x-1)=0
sin^2 x=1
sin x = 1 sinx= -1
x=пи/2 +2пи n x=-пи/2 +2пи n
3)x^3=t
8t^2+7t-1=0
D=81; t1=1/8 t2=-1
x^3=1/8 x^3=-1
x=1/2 x=-1
