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x+1/3 - время туда, час
400/(х+1/3) -скорость туда
2*400/(х+1/3)+(х-2)*(400/(х+1/3)+10)=400 - уравнение
6*40/(3х+1)+(х-2)*(3*40/(3х+1)+1)=40
6*40+(х-2)*(3*40+(3х+1))=40*(3х+1)
240+(х-2)*(121+3х)=120х+40
200+(х-2)*(121+3х)=120х
х=4,(6) = 4 часа 40 минут