Question

Решите уравнение надо 1)x^2/x-1=x2/1-x 2)4x+3/y-7=y^2/7-y 3) x/x+10 = 1/x-8 4)1/3x-1 =x/27-x

Answer 1

$1) x^{2} /(x-1)= x^{2} /(1-x) \ \textless \ =\ \textgreater \ - x^{2} /(1-x)= x^{2} /(1-x), =\ \textgreater \ x=0$
$2) 4x+3/y-7= y^{2} /7-y \ \textless \ =\ \textgreater \ x=( y^{3}-7y^{2} -3)/24y$
$3) \frac{x}{x} +10= \frac{1}{x} -8 =\ \textgreater \ \frac{1}{x}=19 =\ \textgreater \ x= \frac{1}{19}$
$4) \frac{1}{3}x-1= \frac{x}{27}-x =\ \textgreater \ \frac{1}{3}x- \frac{28}{27}x=1 =\ \textgreater \ x=-1,5$