Question

Решите уравнение log^1/2(3x-5)=log^1/2(x^2-3)

Answer 1

(3х-5)=(х^2-3)
3х-5-х^2+3=0
-х^2+3х-2=0|-1
Х^2-3х+2=0
D=9-4*2= 1
Х1=(3-1)/2=1
Х2=(3+1)/2=2