Unit 4 Eating Out
Match the words in A with its explanation in B
1.a quality a) no good
2. abundant b) large quantities
3. customary c) to add to a dish to make it look
attractive
4. distinctive d) how good or bad something is
5. to garnish e) quickly
6.interior f) usual
7. inferior g) inside of building
8. relatively h) usual
9. rapidly i)comparatively
II. Complete the sentences with the above words:
1. design is the art of planning the decoration of the inside a house or an
office
4. These shoes are f good .
5. She made progess and was soon the best in the class.
6. thedi with parsley and serve!
7. We look a supply of food with us when we went hiking in the
mountains
8. He’s a good tennis player.
9. This sauce has a very taste.
Объяснение: Unit 4 Eating Out
Match the words in A with its explanation in B
1.a quality a) no good
2. abundant b) large quantities
3. customary c) to add to a dish to make it look
attractive
4. distinctive d) how good or bad something is
5. to garnish e) quickly
6.interior f) usual
7. inferior g) inside of building
8. relatively h) usual
9. rapidly i)comparatively
II. Complete the sentences with the above words:
1. design is the art of planning the decoration of the inside a house or an
office.
2. It’s to hold the door open for someone who is entering a building
behind you.
3. They were very upset. They had bought goods of quality.
4. These shoes are of good .
5. She made progress and was soon the best in the class.
6. the dish with parsley and serve!
7. We look an supply of food with us when we went hiking in the
mountains.
8. He’s a good tennis player.
9. This sauce has a very taste.
Графики функций у=kx+l и y=x²+bx+c при k= -3; l= -8; b=7; c=16 пересекаются в точках A(-4; 4) и B(-6; 10).
Объяснение:
у=kx+l y=x²+bx+c A(-4; 4); B(-6; 10)
1)Составим уравнение прямой у=kx+l по формуле:
(х-х₁)/(х₂-х₁) = (у-у₁)/(у₂-у₁)
Значения х и у - координаты точек.
х₁= -4 у₁=4
х₂= -6 у₂=10
Подставляем значения х и у в формулу:
(х-(-4)/(-6)-(-4) = (у-4)/(10-4)
(х+4)/(-2) = (у-4)/6 перемножаем крест-накрест, как в пропорции:
6х+24= -2у+8
2у= -6х+8-24
2у= -6х-16
у= -3х-8, искомое уравнение.
k= -3 l= -8.
2)y=x²+bx+c A(-4; 4); B(-6; 10)
Используя координаты данных точек, составим систему уравнений:
4=(-4)²+b*(-4)+c
10=(-6)²+b*(-6)+c
Произвести необходимые действия:
4=16-4b+c
10=36-6b+c
Выразим с через b в двух уравнениях:
-с=16-4b-4 -с=12-4b
-c=36-6b-10 -c=26-6b
Приравняем правые части уравнений, так как левые равны:
12-4b=26-6b
-4b+6b=26-12
2b=14
b=7
Теперь вычислим с:
-с=12-4b
-с=12-4*7
-с=12-28
-с= -16
с=16
Подставляем полученные значения b и c в уравнение:
у=x²+7x+16, искомое уравнение.
