Question

117 5/11t+100,1k+176 4/9t при t=-79,8, k=50

Answer 1

$\displaystyle \tt -117\frac{5}{11}t+100,1k+176\frac{4}{9}t=t\cdot\bigg(175\frac{143}{99}-117\frac{45}{99}\bigg)+100,1k=\\\\=58\frac{98}{99}t+100,1k;\\\\\\npu \ \ \ t=-79,8 \ \ u \ \ k=50:\\\\\\58\frac{98}{99}\cdot(-79,8)+100,1\cdot50=-\frac{5840}{99}\cdot\frac{798}{10}+5005=-\frac{584\cdot266}{33}+5005=\\\\=5005-4707\frac{13}{33}=297\frac{20}{33};$