Question

1.решите неравенство. 5x^2 -6 x +1 меньше или равно 0 2.решите неравенство (х+8)(х-1,5)< 0

Answer 1

1.5x² -6 x +1
5х²-х-5х+1
х(5х-1)-(5х-1)
(х-1)(5х-1)
ну
х-1=0          5х-1=0
х=1             х=$\frac{1}{5}$


(х+8)(х-1,5)<0
(х+8)(х-$\frac{3}{2}$)<0
$\left \{ {x+8\ \textless \ 0} \atop {x- \frac{3}{2}\ \textgreater \ 0}} \right.$
$\left \{ {{x+8\ \textgreater \ 0} \atop {x- \frac{3}{2}\ \textless \ 0 }} \right.$
$\left \{ {{x\ \textless \ -8} \atop {x\ \textgreater \ \frac{3}{2} }} \right.$
x∉∅
х∈(-8,$\frac{3}{2}$)

так????