Question

Решите уравнение (2x-3)(4x+6x+9)-8x=2,7x;

Answer 1

$(2x-3)*(4x+6x+9)-8x=2.7x$
$(2x-3)*(10x+9)-8x= \frac{27}{10}x$
$20x^2+18x-30x-27-8x= \frac{27}{10} x$
$20x^2-20x-27= \frac{27}{10} x$
$200x^2-200x-270=27x$
$200x^2-200x-270-27x=0$
$200x^2-227x-270=0$
$x= \frac{-(-227)\pm \sqrt{(-227)^2-4*200*(-270)} }{2*200}$
$x= \frac{227 \pm \sqrt{51529+216000} }{400}$
$x= \frac{227 \pm \sqrt{267529} }{400}$
$x= \frac{227+ \sqrt{267529} }{400}$
$x= \frac{227- \sqrt{267529} }{400}$
$x_1= \frac{227- \sqrt{267529} }{400}, x_2= \frac{227+ \sqrt{267529} }{400}$