Question

Ссоставления уравнений разность двух чисел равна 42 а разность их квадратов минус 168 найдите эти числа

Answer 1

$\left \{ {{x-y=42} \atop {x^2-y^2=-168}} \right. \\\\ \left \{ {{x-y=42} \atop {(x-y)(x+y)=-168}} \right. \\\\ \left \{ {{x-y=42} \atop {(42(x+y)=-168}} \right. \\\\ \left \{ {{x-y=42} \atop {x+y=-4}} \right. \\\\ \left \{ {{x-y=42} \atop {2x=38}} \right. \\\\ \left \{ {{x-y=42} \atop {x=19}} \right. \\\\ \left \{ {{19-42=y} \atop {x=19}} \right. \\\\ \left \{ {{y=-23} \atop {x=19}} \right.$

Числа 19 и -23