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UR-
Exercise 1. Use modal verbs or their equivalents.
1. The deciduous teeth ... appear at about six months after birth.
2. Teeth ... be kept clean to avoid the development of dental plaque.
3. If a decayed tooth is not treated in time pulpitis ... develop.
4. Although the dentist ... treat dental decay you ... give your teeth the
daily care they need.
5. No dentist ... to stop a tooth if it is too bad. In this case he ... extract it.
6. When a cavity is present in a tooth, the dentist will determine what ...
be done to repair the damage.
7. Adults ... thoroughly brush their teeth at least once a day.
8. Poor mouth hygiene ... lead to infection and the development of tooth
decay.
9. The initial lesion of dental caries ... develop in the occlusal fissures.
10. In case of caries a dentist ... first gain access to it.
11. Caries removal ... start in the area of cavitation.
12. Caries lesions ... occur both on pits and fissures and smooth surfaces.
13. Sometimes even a dentist ... help if disease is neglected.
14. The resistance of enamel to dental caries ... be increased by application
of fluoride to the tooth surface.
15. Fluoridation of water ... make teeth more resistant to caries.​

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Ответ:
polavskaya
polavskaya
16.09.2021

1 will

2 must

3 can

4 would must

5 can will

6 would

7 must

8 can

9 will

10 must

4,6(10 оценок)
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Ответ:
Yarmoshenkobchmd
Yarmoshenkobchmd
16.09.2021
Сначала формулы . затем формулы двойного угла sin2α=2sinαcosα cos2α=cos²α-sin²α=cos²α-(1-cos²α)=2cos²α-1⇒  2cos²α=1+cos2α cos2α=cos²α-sin²α=1-sin²α-sin²α=1-2sin²α⇒  2sin²α=1-cos2α а) сos75°cos105°=cos(90°-15°)·cos(90°+15°)== sin15°(-sin15°)=-sin²15°=-(1-cos30°)/2=(cos30°-1)/2= ((√3/2)-1)/2=0,25√3-0,5б) sin75°sin15°=°sin(90°-15°)sin15°=cos15° sin15°=sin30°/2=1/4=0,25в) sin105°cos15°=sin(180°-75°)cos15°=sin75°cos15°=sin(90°-15°)cos15°=cos15°cos15°=(1+cos30°)/2=(1+(√3/2))/2=0,5 +0,25√3 2 способ формулы cosα·cosβ=0,5cos(α-β)+0,5cos(α+β) sinα·sinβ=0,5cos(α-β)-0,5cos(α+β) sinα·cosβ=0,5sin(α+β)+0,5sin(α-β) а) сos75°cos105°=0,5cos(75°-105°)+0,5cos(75°+105°)=0,5cos(-30°)+0,5 cos180°==0,5· √3/2+0,5·(-1)=0,25√3-0,5б) sin75°sin15°=0,5cos(75°-15°)-0,5cos(75°+15° )=0,5cos60°-0,5 cos90°=0,5·0,5=0,25в) sin105°cos15°=0,5sin(105°+15°)+0,5sin(105°-15°)= =0,5sin120°+0,5sin90°==0,5 sin(180°-60°)+0,5·1=0,5 sin 60°+0,5=0,25√3+0,5
4,7(7 оценок)
Ответ:
ДарьяДуда
ДарьяДуда
16.09.2021
Hello - hello  -what are you doing this weekend?   - nothing  - come with me to the computer club  - what is a "computer club"?   - if you love to play computer games, but you do not have a computer, you can play in a computer club.  - wow, this charge? - yes, but it does not require a lot of money  - good. what do i need to bring?   - if you learn well, then you can take the diary. for good learning are free to play   - can i call someone else?   - yes, of course   - i'll see you on saturday?   - well, goodbye  - goodbye
4,6(39 оценок)
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