105
Объяснение:
Необходимо найти угол АСВ. Обозначим центр точкой О. Построим центральный угол АОВ, так же построим вписанный угол ADB.Для начала определим угловые меры дуг АСВ и ADB. Сказано, что хорда AB делит окружность на две части, градусные величины которых относятся как 5:7. Введём коэффициент пропорциональности х, получим: 5х+7х=360
12х=360
х=30
Значит хорда АВ делит окружность на две части градусные величины которых равны:
дуга асв 5 *30=150
дуга адв 7*30=210
Воспользуемся свойством вписанного угла. Известно, что он равен половине центрального угла, опирающегося на ту же дугу. В данном случае
угол адв =0.5*150=75
Рассмотрим четырёхугольник ADBC. Известно, что сумма противоположных углов четырёхугольника вписанного в окружность равна 1800, значит
угол асв=185-75=105
ответ: 105
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