1.Two years ago I was getting home from school this way.
2. every day I get home from school this way
3. Now I get home from school.
4. I already got home from school
5. Tomorrow I will get home from school in the same way.
6. Two years ago, I turned left into Denham Lane.
7. Every day I turn left into Denham Lane
8. Now I turn left into Denham Lane.
9. I have already turned left into Denham Lane
10. Tomorrow I will turn left into Denham Lane.
11. Two years ago I crossed the road.
12. Every day I cross the road
13. Now I cross the road
14.I have already crossed the road
15. Tomorrow I will cross the road
16. Two years ago I went through the gate and over the bridge
17. Every day I pass through the gate and over the bridge
18.Now I go through the gate and over the bridge
19.I have already passed through the gate and over the bridge
20. Tomorrow I will pass through the gate and across the bridge.
1. The ohmmeter is used to measure the value of resistance while it is connected in paralltl to the resistor.
2. The ammeter is connected in series while the current is being measured.
3. While the value of current in the circuit is measured, the ammeter should be connected in series.
1. Suppose the ammeter scale reads 1.9 amp, the voltmeter scale reads 2.4 V; how much is the value of resistance in the measured circuit?
R = U / I = 2.4 / 1.9 = 1.26 Ohm
2. Suppose the ohmmeter scale reads 75 ohms, the voltmeter scale reads 220 V; how much is the value of current in the measured circuit?
I = U / R = 220 / 75 = 2.9 A
3. Suppose that you have a series circuit consisting of three resistors and a voltage source. R1 = 0.18 ohm, R2= 1.15 ohms, R3 = 2 ohms, I=10 amp. Find the voltage drop across each resistor; find the value of voltage in the circuit.
U1 = R1 * I = 0.18 * 10 = 1.8 V
U2 = R2 * I = 1.15 * 10 = 11.5 V
U3 = R3 * I = 2 * 10 = 20 V
Suppose R1 gets open. What does it result in? I = 0
4. Two resistors are connected in series. R1 = 7,000, R2= 2,200, I = 110 amp. Find the voltage drop across each resistor.
U1 = R1 * I = 7,000 * 110 = 770,000 V
U2 = R2 * I = 2,200 * 110 = 242,000 V
Suppose no current passes through the circuit, what does it result from?
It results from the broken circuit.