В електричному колі паралельно зєднано резистори з опорами R1=60 Ом, R2=120 Ом, R3=40 Ом. До кола прикладено напругу U=120 В. Визначте еквівалентний опір кола, силу струму в нерозгалуженій частині кола, та потужність, яку коло споживає

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Ответ:

liq2354234

11.04.2023

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Ответ:

madishalabaev

11.04.2023

Объяснение:

1) форму параболы ( с вершиной параболы в высшей точке траектории )

2) В начале движения тела с начальной скоростью ( v0 ) проекция которой на ось Ох ( v0x ) равна ( v0cosα ) , a на ось Оу ( v0y ) равна ( v0sinα )

В высшей точки траектории vy = 0 м/с

Поэтому

0 = v0sinα - gt

отсюда

tп. ( время подъема ) = t = ( v0sinα ) / g

Дальность полёта тела будет вычисляться как

L = vxtпол.

Где tпол. ( полное время движения ) = 2tп. = ( 2v0sinα ) / g

L = ( v0cosα2v0sinα ) / g

2sinαcosα = sin2α , поэтому

L = ( v0²sin2α ) / g

Но sin90° = 1 , поэтому если α = 45° , то sin2α = 1

Поэтому именно при угле бросания равным 45° будет максимальная дальность полета

3) В наивысшей точке траектории скорость тела сонаправлена с осью горизонта , поэтому угол между горизонтом и вектором скорости тела в данный момент времени равен 0°

Так как траекторией движения тела брошенного под углом является парабола тогда в конечной точке траектории угол между горизонтом и вектором направления направления скорости будет равен углу между вектором начальным скорости и горизонтом .