Внаправлении, перпендикулярном линиям индукции, влетает в магнитное поле электрон со скоростью 10 мм/с, найдите индукцию поля, если электрон описал в поле окружность радиусом 1см

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Ответ:

митгпош

15.01.2022

B = mv / (qR) =
=(9.1*10^-31 Кг * 10*10^6 м/с) / (1.6*10^-19 Кл *0.01 м)=0.00569 Тл = 5.7 мТл

4,5(70 оценок)

Ответ:

daimon708

15.01.2022

Индукцию магнитного поля находят из второго закона Ньютона и то что сила Лоренца вызывает движение по окружности является центростремительной силой имеем равенство
(mV^2)/R=qVB откуда B=(mV)/qR

4,7(100 оценок)

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Ответ:

Marcelyn

15.01.2022

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4,6(70 оценок)

Ответ:

аграил9

15.01.2022

Объяснение:

1)2кНм- 2000 Н/м

500 мг-0,0005 кг

0,003 МДж- 3000 Дж

0,2 кВт- 200 Вт

2) подвижный блок дает выигрыш в силе в два раза, так как передвигается вместе с грузом что сокращает путь в 2 раза. а так как путь и сила прямо пропорциональны при уменьшении пути , прикладываемая сила тоже уменьшается

3) F1*L1 равно F2*L2

из этого F2 равно F1*L1/L2

получается 50Н*L/2L. сокращаем L и выходит 50Н/2, получается F2 равно 25Н

4) кинетическая энергия равна mV в квадрате/2

подставляем цифры получается 70*400/2 равно 14кДж

5) N равно A/t из этого, t равно A/N

получается 2400Н*5000м/50000 Вт равно 240с

6)формула КПД равна η=Ap/Apoln⋅100%

из этого Ар равна 24кг*10Н/кг*5м равно 1200 Дж

Ароln равна 150Н*10м равно 1500 Дж

потом 1200Дж/1500Дж и умножаем на 100%

получается 80%