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Q1= - r*m. (r - удельная теплота парообразования воды=2300000Дж/кг, m -масса пара=4кг) .
Q1= - 2300000*4= - 9200000Дж ( минус означает, что тепло выделяется) .
Теперь количество теплоты, выделившееся при остывании воды.
Q2=c*m*(t2-t1). (c -удельная теплоёмкость воды=4200Дж/ кг*град, t1- начальная температура воды=100град,
t2-конечная температура воды=20град) .
Q2=4200*4*(20 - 100)= - 1344000Дж. Всё количество теплоты= сумме.
Q=Q1+Q2.
Q= - 9200000 + (-1344000)= - 10544000Дж. ( - 10,544МДж (мегаджоуля)).