Объяснение:
Сумма смежных углов равна 180°
Значит углы, чья сумма =212°,не могут быть смежными, т. к. 212° >180°
Значит, эти углы могут быть только вертикальными.
Сумма вертикальных углов 2 и 3 не может равняться 212°, потому что эти углы острые, т. е. каждый из них < 90°, и их сумма будет < 180°.
Следовательно, углы, чья сумма = 212°, это вертикальные углы 4 и 1:
∠1 + ∠4 = 212°, но, т. к. эти углы вертикальные, а, значит, равны, то
∠1 = ∠4 = 212°/2 = 106°
∠1 + ∠3 = 180°, т. к. они как смежные. Отсюда
∠3 = 180° - 106° =74°
∠3 = ∠2= 74° т. к. они как вертикальные
ответ: ∠1 = ∠4 = 106°, ∠2 = ∠3= 74°
1. S = ½×(4+8)×5 = ½×6×5 = 3×5 = 15 см².
2. S=150, h=S:(½×(a+b)) = 150:(½×(9+11)) = 150:(½×20) = 150:10 = 15 см.
3. Пусть высота будет BH(нужно отметить Н на рисунке). Проведём высоту из точки С, будет она СЕ. Т.к. трапеция равнобедренная, то АН=DE. AH=BH=4 см, ведь угол А=45°, угол Н=90°, соответственно угол В=45° и треугольникк АВН равнобедренный. Из этого, AD=4+5+4 = 13 см.
Найдём площадь: S=½×(5+13)×4 = ½×18×4 = 9×4 = 36 см².
4. Пусть одна часть будет х, тогда BC=3x, AD=4x.
S=½×(3x+4x)×5 = ½×7x×5 = 3,5x×5 = 17,5x -> 17,5x = 35.
x=2 см.
AD=4x = 4×2 = 8 см.
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<1=106°
<2=74°
<3=74°
<4=106°
Объяснение:
<1+<4=212°
<1=<4, вертикальные углы.
<1=212°:2=106°
<4=106°
<1+<2=180°, смежные углы.
<2=180°-<1=180°-106°=74°
<2=<3, вертикальные углы.
<3=74°