#include <iostream>
using namespace std;
int main()
{
int n, m;
int **arr;
int min;
cout << "Enter dimension of array (n/m)" << endl;
cin >> n >> m;
arr = new int *[n];
for (int i = 0; i < n; i++) {
arr[i] = new int[m];
}
for (int i = 0; i < n; i++) {
for (int j = 0; j < m; j++) {
cout << "arr[" << i << "][" << j << "] = ";
cin >> arr[i][j];
}
}
cout << "Your array:" << endl;
for (int i = 0; i < n; i++)
{
for (int j = 0; j < m; j++)
{
cout << arr[i][j] << " ";
}
cout << endl;
}
cout << "Min is: ";
min = arr[0][0];
for (int i = 0; i < n; i++) {
for (int j = 0; j < m; j++) {
if (min > arr[i][j]) {
min = arr[i][j];
}
}
}
cout << min << endl;
return 0;
}
not(a) and (b or not(c))
Код на Python:
for a in range(0,2):
for b in range(0,2):
for c in range(0,2):
f=not(a) and (b or not(c))
print('A = ',a,'B = ',b,'C = ',c,'F = ',f)
б) А и не ( В и или не С) получим такое выражение:
a and (b or not(c))
Код на Python:
for a in range(0,2):
for b in range(0,2):
for c in range(0,2):
f=a and (b or not(c))
print('A = ',a,'B = ',b,'C = ',c,'F = ',f)
в) не ( не А или В и С) преобразуем:
a and (b or c)
Код на Python:
for a in range(0,2):
for b in range(0,2):
for c in range(0,2):
f=a and (b or c)
print('A = ',a,'B = ',b,'C = ',c,'F = ',f)