a.append(k)
l = 0
for i in range(len(a)):
if a[i]>=3:
l = l+1
a[i] = a[i]-3
if l == three:
break
print(l,"тройки")
print(a)
j = 0
for i in range(len(a)):
if a[i]>=2:
j = j+1
a[i] = a[i]-2
if j == two:
break
print(j,"двойки")
print(a)
m = 0
for i in range(len(a)):
if a[i]>=1:
m = m+1
a[i] = a[i] - 1
if m == one:
break
print(m,"одиночки")
print(a)
if l>=three and j>=two and m>=one:
print("YES")
else:
print("NO")
Объяснение:
надеюсь в коде разберешься )
написано в питоне
using namespace std;
int main ()
{
double val1 = 0;
double val2 = 0;
cin >> val1 >> val2;
cout << "Cумма = " << val1+val2 << "/n";
cout << "Разность = " << val1-val2 << "/n";
cout << "Произведение = " << val1*val2 << "/n";
cout << "Частное = " << val1/val2 << "/n";
}