Предположим, что время, через которое лодка и байдарка встретятся = Х.
Тогда расстояние, которое пройдет за это время лодка = 3*Х, а расстояние, которое за это время пройдет байдарка = 8*Х.
У нас получится уравнение :
3Х+8Х=44
11Х=44
Х=44:11
Х=4
Проверим :
3*4+8*4=44
ответ : лодка и байдарка встретятся через 4 часа.
Можно также сложить скорости обоих транспортных средств и узнать, на какое время хватит указанного расстояния сумме скоростей :
44:(3+8)=4
ответ : лодка и байдарка встретятся через 4 часа.
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===== PascalABC.NET =====
-№1-
begin
var (Яблок, Апельсинов, Бананов) :=
ReadInteger3('Число яблок, апельсинов и бананов:');
var ВесЯблок := 100 * Яблок;
var ВесАпельсинов := 150 * Апельсинов;
var ВесБананов := 170 * Бананов;
if ВесЯблок > ВесАпельсинов then
if ВесЯблок > ВесБананов then
Print('Берем яблоки')
else
Print('Берем бананы')
else if ВесАпельсинов > ВесБананов then
Print('Берем апельсины')
else
Print('Берем бананы')
end.
-№2-
begin
var n := ReadInteger('Введите натуральное число;');
var P := new HashSet<integer>; // это множество целых
while n > 0 do
begin
P += n mod 10; // очередную цифру добавляем ко множеству
n := n div 10
end;
P.Count.Println // в множестве все элементы уникальны
end.
1)3+8=11км/ч-скорость сближения
2)44:11=4ч-они встретятся
ответ:через 4 часа