Если имеется в виду (a*b);
то будет 48
Тоесть такой код:
a=4; b=2; c=6
a=(a*b)*c
print(a)
Ну а если так:
Ну а если так:Выйдет ошибка:
Traceback (most recent call last):
Traceback (most recent call last): File "/data/user/0/ru.iiec.pydroid3/files/accomp_files/iiec_run/iiec_run.py", line 31, in <module>
Traceback (most recent call last): File "/data/user/0/ru.iiec.pydroid3/files/accomp_files/iiec_run/iiec_run.py", line 31, in <module> start(fakepyfile,mainpyfile)
Traceback (most recent call last): File "/data/user/0/ru.iiec.pydroid3/files/accomp_files/iiec_run/iiec_run.py", line 31, in <module> start(fakepyfile,mainpyfile) File "/data/user/0/ru.iiec.pydroid3/files/accomp_files/iiec_run/iiec_run.py", line 30, in start
Traceback (most recent call last): File "/data/user/0/ru.iiec.pydroid3/files/accomp_files/iiec_run/iiec_run.py", line 31, in <module> start(fakepyfile,mainpyfile) File "/data/user/0/ru.iiec.pydroid3/files/accomp_files/iiec_run/iiec_run.py", line 30, in start exec(open(mainpyfile).read(), __main__.__dict__)
Traceback (most recent call last): File "/data/user/0/ru.iiec.pydroid3/files/accomp_files/iiec_run/iiec_run.py", line 31, in <module> start(fakepyfile,mainpyfile) File "/data/user/0/ru.iiec.pydroid3/files/accomp_files/iiec_run/iiec_run.py", line 30, in start exec(open(mainpyfile).read(), __main__.__dict__) File "<string>", line 2, in <module>
Traceback (most recent call last): File "/data/user/0/ru.iiec.pydroid3/files/accomp_files/iiec_run/iiec_run.py", line 31, in <module> start(fakepyfile,mainpyfile) File "/data/user/0/ru.iiec.pydroid3/files/accomp_files/iiec_run/iiec_run.py", line 30, in start exec(open(mainpyfile).read(), __main__.__dict__) File "<string>", line 2, in <module>NameError: name 'ab' is not defined
#include <iostream>
using namespace std;
int main() {
int a, b, x;
a = 0;
b = 5;
x = 4;
if (a > b) {
if (x > b && x < a) cout << "В диапозоне";
else cout << "Не в диапозоне";
}
elif (a < b) {
if (x > a && x < b) cout << "В диапозоне";
else cout << "Не в диапозоне";
}
else cout << "Диапозона нет :)";
}