###язык Python##
###1##
N=int(input())
if(N<32 and N%3!=0 or N<0):
print("YES")
else:
print("NO")
###2##
N=int(input())
if(N%2==0 or N>400 and N<500):
print("YES")
else:
print("NO")
###3##
N=int(input())
if(len(str(N))==3 and str(N)[-1]=='9'):
print("YES")
else:
print("NO")
###4##
N=int(input())
if(N>=345 and N<543 or N%7==0):
print("YES")
else:
print("NO")
###5##
N=int(input())
if(N%3==0 or str(N)[-1]=='0'):
print("YES")
else:
print("NO")
###6##
N=int(input())
if(N%2==0 and int(str(N)[-2])>5):
print("YES")
else:
print("NO")
###7##
N=int(input())
if(N%2!=0 and len(str(N))==3):
print("YES")
else:
print("NO")
##8##
a=int(input())
b=int(input())
if(int(str(a)[-4])>int(str(b)[-4])):
print("YES")
else:
print("NO")
##9##
a=int(input())
b=int(input())
if(int(str(a)[-3])%2==0 and b%2!=0):
print("YES")
else:
print("NO")
##10##
a=int(input())
b=int(input())
if(a%8>4 and b%12<5):
print("YES")
else:
print("NO")
##11##
a=int(input())
b=int(input())
if(a%3!=0 and b%3!=0):
print("YES")
else:
print("NO")
##12##
a=int(input())
b=int(input())
if((a*b)%3==0):
print("YES")
else:
print("NO")
##13##
a=int(input())
b=int(input())
if(a%23<14 and b%22>15):
print("YES")
else:
print("NO")
##14##
a=int(input())
b=int(input())
if(a%b==0 or b%a==0):
print("YES")
else:
print("NO")
##15##
a=int(input())
b=int(input())
if(str(a)[-1]=='6' and str(b)[-4]=='6'):
print("YES")
else:
print("NO")
1) ((N mod 3=0) or (N mod 7=0)) and (N mod 5<>0)
2) (((N mod 100) div 10)>((N mod 1000) div 100)) and (N mod 3=0)
3) (N mod 2=0) or ((N >400) and (N<500))
4) (N mod 6=0) and (N mod 7<>0)
5) ((N>9) and (N<100)) and ((N mod 10=6) or (N div 10=6) ))div 10))
6) (N mod 2=0) and (N mod 3=0)
7) ((N>99) and (N<1000)) and (N mod 2<>0)
8) ((N>9) and (N<100)) and ((N div 10) mod 2=0)
9) ((N<=77) or (N>=88))
10) (N mod 2<>0) or (N <=3) or (N mod 7<>0)
11) ((a>9) and (a<100)) and (b>0)
12) (a mod b=0) or (b mod a=0)
13) (((a mod 100) div 10) mod 2=0) and (((a mod 100) div 10) mod 2=0)
14) (a*b) mod 3=0
15) ((a+b) mod 2=0) and ((a*b) mod 2<>0)
16) ((a>9) and (a<100)) and (b<53)
17) ((a mod 1000) div 100=2) or ((b mod 1000) div 100=2)
18) (a>0) or (b>0)
19) (a mod 10)>((a mod 100) div 10)
20) (a>0) and (b>0)
ответ: 2
Подставим числа и получим уравнение:
((4+1+1)*b+1)*b = 26
(6*b+1)*b = 26
6b² + b - 26 = 0
D (дискриминант) = 1 + 624 = 625
b1 = (-1+25) / 12 = 2
b2 = (-1-25) / 12 = -2,1(6) - не подходит, так как не является натуральным числом