Question

Надосоставить схему алгоритма и программу для вычисления значенийфункции y для заданных значений переменной x и постоянных а, в, h.1. y = xsinx/cosx; a = -1.6, b = 1.6, h = 0.22. y = tgx2 + ctgx2; a = -2, b = 2, h=0.53. y = ln(x2 -9)/x; a = -6, b = 6, h = 14. y = xln(cosx); a = -3, b = 3, h = 0.35. y = tgx/x; a = -2, b = 2, h = 0.26. y = sinx/(x-5); a = -6, b = 6, h = 0.57. y = x/(1-cosx); a = -4, b = 4, h = 0.58. y = 1/xtg(x/2); a = -3, b = 3, h = 0.59. y = 1/(x2 -3); a = -4, b = 4, h = 0.510. y = 1/ln(x2/8); a = -3, b = 3, h = 0.611. y = 1/x ctg(x/3); a = -4, b = 4, h = 0.512. y = ln(16-x2)/x ex; a = -6, b = 6, h = 0.513. y = x tg x/ lnx; a = -3, b = 3, h = 0.514. y = x2ln|x|/sinx; a = -2, b = 2, h = 0.215. y = x/sinx+ ln(x2 - 4); a = - 6, b = 6, h = 0.516. y = x2cosx/ln(x2-1); a = -2, b = 2, h = 0.117. y = xsinx/ln(x2-9); a = -5, b = 5, h = 0.518. y = x2/(cosx+ln(x2-1)); a = -2, b = 2, h = 0.219. y = (x2+ tgx)/ln(x2-4); a = -4, b = 4, h = 0.820. y = (x2- cosx)/xln(x2-1); a = -2, b = 2, h = 0.2​