Mr(CoCl2) = Ar(Co) + 2Ar(Cl) = 59 + 2 * 35.5 = 130
Mr(H2O) = 2Ar(H) + Ar(O) = 2 * 1 + 16 = 18
Mr(CoCl2 * 6H2O) = Mr = Mr(CoCl2) + 6Mr(H2O) = 130 + 6 * 18 = 238
w(H2O) = 6Mr(H2O) / Mr = 108 / 238 = 0.4538 = 45.38%
Mr(CoCl2 * 4H2O) = Mr = Mr(CoCl2) + 4Mr(H2O) = 130 + 4 * 18 = 202
w(H2O) = 4Mr(H2O) / Mr = 72 / 202 = 0.4538 = 0.3564 = 35.64%
Mr(CoCl2 * H2O) = Mr = Mr(CoCl2) + Mr(H2O) = 130 + 1 * 18 = 148
w(H2O) = Mr(H2O) / Mr = 18 / 148 = 0.1216 = 12.16%
CoCl2*6H20 - 45.38%
CoCl2*4H2O - 35.64%
CoCl2*H2O - 12.16%
Mr(CoCl2) = Ar(Co) + 2Ar(Cl) = 59 + 2 * 35.5 = 130
Mr(H2O) = 2Ar(H) + Ar(O) = 2 * 1 + 16 = 18
Mr(CoCl2 * 6H2O) = Mr = Mr(CoCl2) + 6Mr(H2O) = 130 + 6 * 18 = 238
w(H2O) = 6Mr(H2O) / Mr = 108 / 238 = 0.4538 = 45.38%
Mr(CoCl2 * 4H2O) = Mr = Mr(CoCl2) + 4Mr(H2O) = 130 + 4 * 18 = 202
w(H2O) = 4Mr(H2O) / Mr = 72 / 202 = 0.4538 = 0.3564 = 35.64%
Mr(CoCl2 * H2O) = Mr = Mr(CoCl2) + Mr(H2O) = 130 + 1 * 18 = 148
w(H2O) = Mr(H2O) / Mr = 18 / 148 = 0.1216 = 12.16%
CoCl2*6H20 - 45.38%
CoCl2*4H2O - 35.64%
CoCl2*H2O - 12.16%
Объяснение:
Какие продукты будут у реакции на фото
H
С6Н5 - СНСl2 + 2 KOH = С6Н5 - С- OH > С6Н5 - С=O
OH - H2O I
H
бензальдегид