CaO(оксид кальция)+H2O(вода)=Ca(OH)2(гидроксида кальция)
nCa(OH)2=mCa(OH)2/M Ca(OH)2=37г/74г/моль=0,5моль
nCaO=nCa(OH)2=0.5моль
mCaO=M CaO*n CaO=56г/моль*0,5моль=28г
ответ:28г
Є декілька в класифікації солей:
За кислотою, якій відповідає ця сіль (хлориди, фосфати, нітрати)
За середовищем : Середні (нормальні) солі, Кислі солі, Основні солі
Солі за своїм складом поділяються на середні, кислі, основні та подвійні.
· середні (нормальні);
Утворюються при повному заміщенні атомів Гідрогену в молекулах кислот атомами металів. Наприклад, Na2CO3, BaCl2.
· кислі;
Утворюються при неповному заміщенні атомів Гідрогену в молекулах кислот атомами металів. Наприклад, NaHCO3, KH2PO4.
· основні;
Утворюються при неповному заміщенні гідроксильних груп в молекулах основ кислотними залишками. Наприклад, MgOHCl, BaOHBr.
· подвійні;
Утворюються при заміщенні атомів Гідрогену в молекулах кислот двома різними металами. Наприклад, KAlSO4, K2NaPO4.
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1)Запсываем уравнение реакции:
CaO + H2O = Ca(OH)2
2)Вычисляем количество вещества гидроксида кальция:
M(Ca(OH)2) = 40 + 2 x 16 + 2 x 1 = 74г/моль
n(Ca(OH)2) = m/M = 37г/74г/моль = 0,5моль
3)Находим количество вещества оксида кальция. Определяем соотношение оксида и гидроксида кальция по уравнению реакции:
n(CaO) = n(Ca(OH)2) = 0,5моль
4)Определяем массу оксида кальция:
M(CaO) = 40 + 16 = 56г/моль
m(CaO) = n x M = 0,5моль х 56г/моль = 28г