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Дано: рЕШЕНИЕ:
m(Fe(OH)3)=32.1г n=m/M
Найти(H2-?) Mr( Fe(OH)3 )=Ar(Fe)+3Ar(O)+3Ar(H) =56+48+3=107
M( Fe(OH)3 )=107 г/моль
n ( Fe(OH)3 ) =32.1г/107 г/моль=0.3моль
0.3 моль х моль
2Fe(OH)3 = Fe2O3+3H2O
2 моль 3 моль
n(H2O)=0.45 моль
0.45 моль х
2H2O= 2H2+O2
2 моль 2 моль
n(H2)=0.45моль
V=Vm*n
V(H2)=22.4 дм3/моль*0,45моль=10.08 дм3
ответ: V(H2)= 10.08 дм3
Жду и лучший ответ)