1. Прийом «Вилучи зайве» 1) Ca, MgO, NaCl, H 2 SO 4 ; 2) SO 2 , H 2 CO 3 , Na 2 O, CuO; 3) K 2 O, Ag - id2131760020211112 от mariana20021 12.11.2021 19:41

Question

Химия: 1. Прийом «Вилучи зайве» 1) Ca, MgO, NaCl, H 2 SO 4 ; 2) SO 2 , H 2 CO 3 , Na 2 O, CuO; 3) K 2 O, Ag 2 O, CO 2 , FeO; 4) SiO 2 , MnO, P 2 O 5 , N 2 O 5 ; 5) HCl, H 2 CO 3 , K 2 SO 4 , H 3 PO 4 .

mariana20021 · Accepted Answer

Mr[K2SO4] = Ar[K] * 2 + Ar[S] + Ar[O] * 4 = 39.0983 * 2 + 32.065 + 15.9994 * 4 = 174.2592

Mr[LiOH] = Ar[Li] + Ar[O] + Ar[H] = 6.941 + 15.9994 + 1.00794 = 23.94834

Mr[CuNO3] = Ar[Cu] + Ar[N] + Ar[O] * 3 = 63.546 + 14.0067 + 15.9994 * 3 = 125.5509

Mr[CaBr2] = Ar[Ca] + Ar[Br] * 2 = 40.078 + 79.904 * 2 = 199.886

Mr[MgCO3] = Ar[Mg] + Ar[C] + Ar[O] * 3 = 24.305 + 12.0107 + 15.9994 * 3 = 84.3139

Mr[CaSO3] = Ar[Ca] + Ar[S] + Ar[O] * 3 = 40.078 + 32.065 + 15.9994 * 3 = 120.1412

Mr[CaCl2] = Ar[Ca] + Ar[Cl] * 2 = 40.078 + 35.453 * 2 = 110.984

Mr[BaSO4] = Ar[Ba] + Ar[S] + Ar[O] * 4 = 137.327 + 32.065 + 15.9994 * 4 = 233.3896

Mr[H3PO4] = Ar[H] * 3 + Ar[P] + Ar[O] * 4 = 1.00794 * 3 + 30.973762 + 15.9994 * 4 = 97.995182

Объяснение:

1. Прийом «Вилучи зайве» 1) Ca, MgO, NaCl, H 2 SO 4 ; 2) SO 2 , H 2 CO 3 , Na 2 O, CuO; 3) K 2 O, Ag 2 O, CO 2 , FeO; 4) SiO 2 , MnO, P 2 O 5 , N 2 O 5 ; 5) HCl, H 2 CO 3 , K 2 SO 4 , H 3 PO 4 .

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