дано
m(ppaNaCL) = 292.5 g
W(NaCL) = 10%
m(ppa AgNO3) = 136 g
W(AgNO3) = 25%
m(AgCL) - ?
NaCL+AgNO3-->AgCL+NaNO3
m(NaCL) = m(ppa NaCL) * W(NaCL) / 100% = 292.5 *10 / 100 = 29.25 g
m(AgNO3) = m(ppa AgNO3) * W(AgNO3) / 100% = 136 * 25 / 100 = 34 g
M(NaCL) = 58.5 g/mol
n(NaCL) = m(NaCL) / M(NaCL) = 29.25 / 58.5 = 0.5 mol
M(AgNO3) = 170 g/mol
n(AgNO3) = m(AgNO3) / M(AgNO3) = 34 / 170 = 0.2 mol
n(NaCL) > n(AgNO3)
n(AgNO3) = n(AgCL) = 0.2 mol
M(AgCL) = 143,5 g/mol
m(AgCL) = n(AgCL) * M(AgCL) = 0.2*143.5 = 28.7 g
ответ 28.7 гр
Объяснение:
1)Растительные пигменты помидоров, моркови
2)2CH2=CH-CH=CH2+11O2= 8Co2+6H2o
3)СН2=СН-СН=СH2 = (нагревание) С2Н2=C2H2+H2
4)СН2=СН-СН=Сн2+Br2 = CHBr-CH=CH-CH2+HBr
5)СН2=СН-СН=Сн2+Н2 = CH3-CH=CH-CH3
6)nCH2=CH-CH+CH2 = (-CH2-CH=CH-CH2-)n
7)не обесцвечивают их