относительная молекулярная масса равна сумме атомных масс
М(NaOH)=23+16+1=40 г/моль
М(Ca(NO3)2)=40+2*14+6*16=40+28+96=164 г/моль
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М (NaOH)=23+16+1=40
M (Ca(NO3)2)=40+(14+16х3)х2=40+62х2=164