1. Fe + 2HBr = FeBr2 + H2 ↑
2Al +3H2SO4 = Al2(SO4)3 + 3H2 ↑
Cu(OH)2 + 2HCl = CuCl2 + 2H2O
S + 3F2 = SF6
2. H2(I)S(II), S(VI)O3(II), N(III)H3(I), C(IV)O2(II), C(IV)H4(I)
3. H2SO4
ω(H) = 2Ar(H)*100/M(H2SO4)
ω(H) = 200/2 + 32 + 64
ω(H) = 2%
ω(S) = Ar(S)*100/M(H2SO4)
ω(S) = 3200/98
ω(S) = 32,7%
ω(O) = 4Ar(O)*100/M(H2SO4)
ω(O) = 6400/98
ω(O) = 65,3%
Na2SO4
ω(Na) = 2Ar(Na)*100/M(Na2SO4)
ω(Na) = 2*23*100/46 + 32 + 64
ω(Na) = 2*23*100/46 + 32 + 64
ω(Na) = 32,4%
ω(S) = Ar(S)*100/M(Na2SO4)
ω(S) = 3200/142
ω(S) = 22,5%
ω(O) = 4Ar(O)*100/M(Na2SO4)
ω(O) = 6400/142
ω(O) = 45,1%
4.
N = m /(M · 1 а. е. м.) = m/(M*1.66057 · 10 ^-27 кг)
Относительная атомная масса меди = 64
У нас 3 моль, значит 64 * 3 = 192 г
N = 0,192кг/(64*1.66057 · 10 ^-27 кг) = 0,001807 * 10^+27 = 1,807*10^+24
2. 2 C2H5OH + 2 O2 ---> 2 CH3COOH + 2 H2O
3. CH3COOH + NaOH > CH3COONa + H2O