CIVII20II7
Объяснение:
определим валентность хлора в его соединении с кислородом — Cl2O7.
1. Записываем известную валентность кислорода над формулой. Неизвестную валентность обозначаем буквой x:
Clx2OII7.
2. Находим сумму единиц валентности каждого элемента. Для этого его валентность умножаем на число атомов:
x⋅2=2⋅7.
3. Вычисляем x:
2x=14,x=14:2=7.
Валентность хлора равна VII:
ClVII2OII7.
Составление формулы бинарного соединения по валентностям химических элементов
Если известны валентности двух элементов, то можно составить формулу их соединения.
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Must Waste More Time...
Pl+ H2O реакция не идёт
Ag+ H2O реакция не идёт
2 Al+ 6 HCl= 2 AlCl3+ 3H2
Ag+ NiSO4= AgSO4+ Ni