Объяснение:
Mr(K2CO3) = 39*2 + 12 + 16*3 =138
W(K) = Ar(K) *n / Mr(K2CO3) *100% =39*2 / 138 *100% =56%
W(C) = Ar(C) *n / Mr(K2CO3) *100% = 12*1 / 138 *100% =9%
W(O) = Ar(O) *n / Mr(K2CO3) *100% = 16*3 / 138 *100% =35%
Mr(CuO) = 64 + 16 = 80
W(Cu) = Ar(Cu) *n / Mr(CuO) *100% = 64*1 / 80 *100% = 80%
W(O) = Ar(O) *n / Mr(CuO) *100% = 16*1 / 80 *100% = 20%
Mr(Ca3(PO4)2) = 40*3 + 31*2 + 16*8 =310
W(Ca) = Ar(Ca) *n / Mr(Ca3(PO4)2) *100% = 40*3 / 310 *100% =39%
W(P) = Ar(P) *n / Mr(Ca3(PO4)2) *100% = 31*2 / 310 *100% =20%
W(O) = Ar(O) *n / Mr(Ca3(PO4)2) *100% = 16*8 / 310 *100% =41%
2HgO->2Hg+O2
n(HgO)=11/217=0.0507 моль
По ур-ю:
n(Hg)=n(HgO)=0.0507 моль
m(Hg)=0.0507×201=10.19 г
По ур-ю:
n(O2)=1/2n(HgO)=0.0253 моль
V(O2)=0.0253×22.4=0.568 л
ответ: 10.19 г, 0.568 л