Question

Интегралы.решите любые 3 примера

Answer 1

$1. 2-\sqrt{2}$

$5. 1-\sqrt{3}$

$6. \frac{3\sqrt{3}}{2}$

Пошаговое объяснение:

$1. \int\limits^\frac{\pi }{2} _\frac{\pi}{4}{2cosx} \, dx = 2sinx /_{\frac{\pi}{4}}^{\frac{\pi}{2}}=\\ =2(sin{\frac{\pi}{2}}-sin{\frac{\pi}{4}})=2(1-\frac{\sqrt{2}}{2})=2-\sqrt{2}$

$5. \int\limits^\frac{\pi }{3} _\frac{\pi}{6}{2sinx} \, dx = -2cosx /_{\frac{\pi}{6}}^{\frac{\pi}{3}}=\\ =-2(cos{\frac{\pi}{3}}-cos{\frac{\pi}{6}})=-2(\frac{1}{2}-\frac{\sqrt{3}}{2} )=1-\sqrt{3}$

$6. \int\limits^\frac{\pi }{3} _0{3cosx} \, dx = 3sinx /_{0}^{\frac{\pi}{3}}=\\ =3(sin{\frac{\pi}{3}}-sin0)=3(\frac{\sqrt{3}}{2}-0)=\frac{3\sqrt{3}}{2}$