Question

- решите уравнение:
а) 37x = 259; г) (38 + b) : 12 = 840;
б) 252 : у = 21; д) 140р — 30) = 630;
в) 2 : 18 = 6; е) (43 – s) : 17 = 289.
525. ​

Answer 1

$37x = 259 \\ x = \frac{259}{37} \\ x = 7$

$(38 + b) \div 12 = 840 \\ 38 + b = 840 \times 12 \\ 38 + b = 10080 \\ b = 10080 - 38 \\ b = 10042$

$252 \div y = 21 \\ y = 252 \div 21 \\ y = 12$

$140p - 30 = 630 \\ 140p = 30 + 630 \\ 140p = 660 \\ p = 660 \div 140 \\ p = 4 \frac{5}{7}$

$(43 - s) \div 17 = 289 \\ 43 - s = 17 \times 289 \\ 43 - s = 4913 \\ s = 43 - 4913 \\ s = - 4870$