Question

6m^2-3mn+2m-n/6m^2+3mn+2m+n, ввчислите её значения при n/m=4

Answer 1

Пошаговое объяснение:

$\displaystyle\\\frac{6m^2-3mn+2m-n}{6m^2+3mn+2m+n}=\frac{3m(2m-n)+(2m-n)}{3m(2m+n)+(2m+n)}=\\\\\\\frac{(2m-n)(3m+1)}{(2m+n)(3m+1)} =\frac{2m-n}{2m+n} \\\\\\n/m=4;\ =\ n=4m\\\\\\\frac{2m-4m}{2m+4m} =\frac{-2m}{6m} =-\frac{1}{3} \\\\$