Question

Упростите выражения: 1)√75+√48-√300

2)3√8-√50+2√18

3)√242-√200+√8

4)√75-0.1√300-√27

Answer 1

$\sqrt{75} + \sqrt{48} - \sqrt{300} = \sqrt{ {5}^{2} \times 3 } + \sqrt{ {4}^{2} \times 3} - \sqrt{ {10}^{2} \times 3 } = 5 \sqrt{3} + 4 \sqrt{3} - 10 \sqrt{3} = - \sqrt{3}$

$3 \sqrt{8} - \sqrt{50} + 2 \sqrt{18} = 3 \sqrt{ {2}^{2} \times 2 } - \sqrt{ {5}^{2} \times 2} + 2 \sqrt{ {3}^{2} \times 2} = 6 \sqrt{2} - 5 \sqrt{2} + 6 \sqrt{2} = 7 \sqrt{2}$

$\sqrt{242} - \sqrt{200} + \sqrt{8} = \sqrt{ {11}^{2} \times 2 } - \sqrt{ {10}^{2} \times 2} + \sqrt{ {2}^{2} \times 2} = 11 \sqrt{2} - 10 \sqrt{2} + 2 \sqrt{2} = 3 \sqrt{2}$

$\sqrt{75} - \frac{1}{10} \sqrt{300} - \sqrt{27} = \sqrt{ {5}^{2} \times 3 } - \frac{1}{10} \sqrt{ {10}^{2} \times 3 } - \sqrt{ {3}^{2} \times 3} = 5 \sqrt{3} - \sqrt{3} - 3 \sqrt{3} = \sqrt{3}$

Answer 2

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Пошаговое объяснение:

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