Question

Номер 484 решите уравнение целых1/8=10целых2/9;
2)х+29целых7/8=51целая5/12;
3)11целых1/12-х=9целых1/8;
4)60целых3/14-х=41целая4/21;
5)77целых4/15-х=59целых8/9;
6)61целая5/8-х=52целых1/6.

Answer 1

вот на фото решение

Пошаговое объяснение:

в конце написано х=17 целых 17/45

Answer 2

1) $x + \frac{41}{8} = \frac{92}{9}$

x = $\frac{92}{9} - \frac{41}{8}$

x = $\frac{736-369}{72}$

x = $\frac{367}{72}$

x = $5\frac{7}{72}$

2) $x + \frac{239}{8} = \frac{617}{12}$

x = $\frac{617}{12} - \frac{239}{8}$

x = $\frac{1234-717}{24}$

x = $\frac{517}{24}$

x = $21\frac{13}{24}$  

3) $\frac{133}{12} - x = \frac{73}{8}$

$-x = \frac{73}{8} - \frac{133}{12}$

-x = $\frac{219-266}{24}$

-x = $-\frac{47}{24}$

x = $1\frac{23}{24}$

4) $\frac{843}{14} - x = \frac{865}{21}$

$-x = \frac{865}{21} - \frac{843}{14}$

-x = $\frac{1730-2529}{42}$

-x = $-\frac{799}{42}$

x = $19\frac{1}{42}$  

5) $\frac{1159}{15} - x = \frac{539}{9}$

$-x = \frac{539}{9} - \frac{1159}{15}$

-x = $\frac{2695-3477}{45}$

-x = $-\frac{782}{45}$

x = $17\frac{17}{45}$  

6) $\frac{493}{8} - x = \frac{313}{6}$

$-x = \frac{313}{6} - \frac{493}{8}$

-x = $\frac{1252-1479}{24}$

-x = $-\frac{227}{24}$

x = $9\frac{11}{24}$