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Belayalbina2512
Belayalbina2512
22.03.2022 03:17 •  Математика

1. Делится ли сумма: а) 100+250+75+500 делится на 25
б) 18+27+36+81 делится на 9
в) 44+68+88+96 делится на 4
г) 18+180+36+21 делится на 6
д) 16+42+52+23 делится на 2
2. Делится ли произведение:
а) 16*250 делится на 8
б) 26*75*32 делится на 20
в) 81*15*36 делится 27.
Мне нужно решением!


1. Делится ли сумма: а) 100+250+75+500 делится на 25б) 18+27+36+81 делится на 9в) 44+68+88+96 делитс

👇
Ответ:
pasagilazutdino
pasagilazutdino
22.03.2022

См. Пошаговое объяснение

Пошаговое объяснение:

1. Делится ли сумма:

а) 100+250+75+500 делится на 25  - да, т.к. каждое слагаемое делится на 25.

б) 18+27+36+81 делится на 9  - да, т.к. каждое слагаемое делится на 9.

в) 44+68+88+96 делится на 4  - да, т.к. каждое слагаемое делится на 4.

г) 18+180+36+21 делится на 6  - нет, т.к. одно из слагаемых (21) не делится на 6;

д) 16+42+52+23 делится на 2  - нет, т.к. одно из слагаемых (23) не делится на 2;

2. Делится ли произведение:

а) 16*250 делится на 8  - да, т.к. один из сомножителей (16) делится на 8.

б) 26*75*32 делится на 20  - да, т.к. в результате умножения получится число, оканчивающееся двумя нулями.

в) 81*15*36 делится 27​ - да, т.к. один из сомножителей (81) делится на 27.

4,6(79 оценок)
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Ответ:
ROMMIT2
ROMMIT2
22.03.2022

Пошаговое объяснение:

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4,4(68 оценок)
Ответ:
анна2255
анна2255
22.03.2022

Смотрите.

1) Обозначаем t — сколько времени они шли в первый день, тогда (t-1) — сколько во второй.

2) Теперь следующее соотношение — про 6 километров. Пускай в первый день они км, а во второй день — s2, тогда нам дано:

s1-s2=6.

3) Вспоминая, что расстояние=время*скорость (s=v*t), подставляем в эту формулу вместо s1 и s2:

(3,5*t)-(3*(t-1))=6.

Упрощаем:

3,5t-3t+3=6;

0,5t=3;

t=6.

ответ: Таким образом, в первый день они шли 6 часов. Во второй день — 6-1=5 (часов во второй день — 3*5 = 15 (км)

Пошаговое объяснение:

4,7(15 оценок)
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