Question

35-K>19 c-36<25 d+16>23 724:k>3​

Answer 1

$35 - k 19 \\ - k 19 - 35 \\ - k 16 \\ k < 16$

k∈(-∞,16)

$c - 36 < 25 \\ c < 25 + 36 \\ c < 61$

c∈(-∞,61)

$d + 16 23 \\ d 23 - 16 \\ d 7$

d∈(7,+∞)

$724 \div k 3 \\ \frac{724}{k} 3 \\ \frac{724}{k} - 3 0 \\ \frac{724 - 3k}{k} 0 \\$

$k∈(0. \frac{724}{3} )$